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This problem builds on two-sum. Complete that first, then load your solution to continue.
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0.
Notice that the solution set must not contain duplicate triplets.
Find all unique triplets in the array which gives the sum of zero. This is a classic two-pointer problem that extends the Two Sum pattern.
threeSum([-1, 0, 1, 2, -1, -4]); // [[-1, -1, 2], [-1, 0, 1]]
threeSum([0, 1, 1]); // []
threeSum([0, 0, 0]); // [[0, 0, 0]]